3(3x-2)-3=3(x-3)+18

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Solution for 3(3x-2)-3=3(x-3)+18 equation: 



3(3x-2)-3=3(x-3)+18

We move all terms to the left:

3(3x-2)-3-(3(x-3)+18)=0

We multiply parentheses

9x-(3(x-3)+18)-6-3=0



We calculate terms in parentheses: -(3(x-3)+18), so:

3(x-3)+18

We multiply parentheses

3x-9+18

We add all the numbers together, and all the variables

3x+9

Back to the equation:

-(3x+9)



We add all the numbers together, and all the variables

9x-(3x+9)-9=0

We get rid of parentheses

9x-3x-9-9=0

We add all the numbers together, and all the variables

6x-18=0

We move all terms containing x to the left, all other terms to the right

6x=18

x=18/6

x=3

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