3(3x-2)-7x-1=6(2x-7)-15x

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Solution for 3(3x-2)-7x-1=6(2x-7)-15x equation: 



3(3x-2)-7x-1=6(2x-7)-15x

We move all terms to the left:

3(3x-2)-7x-1-(6(2x-7)-15x)=0

We add all the numbers together, and all the variables

-7x+3(3x-2)-(6(2x-7)-15x)-1=0

We multiply parentheses

-7x+9x-(6(2x-7)-15x)-6-1=0



We calculate terms in parentheses: -(6(2x-7)-15x), so:

6(2x-7)-15x

We add all the numbers together, and all the variables

-15x+6(2x-7)

We multiply parentheses

-15x+12x-42

We add all the numbers together, and all the variables

-3x-42

Back to the equation:

-(-3x-42)



We add all the numbers together, and all the variables

2x-(-3x-42)-7=0

We get rid of parentheses

2x+3x+42-7=0

We add all the numbers together, and all the variables

5x+35=0

We move all terms containing x to the left, all other terms to the right

5x=-35

x=-35/5

x=-7

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