3(3x-2)=2(x+1)

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Solution for 3(3x-2)=2(x+1) equation: 



3(3x-2)=2(x+1)

We move all terms to the left:

3(3x-2)-(2(x+1))=0

We multiply parentheses

9x-(2(x+1))-6=0



We calculate terms in parentheses: -(2(x+1)), so:

2(x+1)

We multiply parentheses

2x+2

Back to the equation:

-(2x+2)



We get rid of parentheses

9x-2x-2-6=0

We add all the numbers together, and all the variables

7x-8=0

We move all terms containing x to the left, all other terms to the right

7x=8

x=8/7

x=1+1/7

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