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3(3x-2)=2(x+4)
We move all terms to the left:
3(3x-2)-(2(x+4))=0
We multiply parentheses
9x-(2(x+4))-6=0
We calculate terms in parentheses: -(2(x+4)), so:We get rid of parentheses
2(x+4)
We multiply parentheses
2x+8
Back to the equation:
-(2x+8)
9x-2x-8-6=0
We add all the numbers together, and all the variables
7x-14=0
We move all terms containing x to the left, all other terms to the right
7x=14
x=14/7
x=2
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