3(3x-2)=3(1-6x)

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Solution for 3(3x-2)=3(1-6x) equation: 



3(3x-2)=3(1-6x)

We move all terms to the left:

3(3x-2)-(3(1-6x))=0

We add all the numbers together, and all the variables

3(3x-2)-(3(-6x+1))=0

We multiply parentheses

9x-(3(-6x+1))-6=0



We calculate terms in parentheses: -(3(-6x+1)), so:

3(-6x+1)

We multiply parentheses

-18x+3

Back to the equation:

-(-18x+3)



We get rid of parentheses

9x+18x-3-6=0

We add all the numbers together, and all the variables

27x-9=0

We move all terms containing x to the left, all other terms to the right

27x=9

x=9/27

x=1/3

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