3(3x-2)=3(3x+1)+3

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Solution for 3(3x-2)=3(3x+1)+3 equation: 



3(3x-2)=3(3x+1)+3

We move all terms to the left:

3(3x-2)-(3(3x+1)+3)=0

We multiply parentheses

9x-(3(3x+1)+3)-6=0



We calculate terms in parentheses: -(3(3x+1)+3), so:

3(3x+1)+3

We multiply parentheses

9x+3+3

We add all the numbers together, and all the variables

9x+6

Back to the equation:

-(9x+6)



We get rid of parentheses

9x-9x-6-6=0

We add all the numbers together, and all the variables

-12!=0

There is no solution for this equation

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