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3(3x-2)=3+5(x+3)
We move all terms to the left:
3(3x-2)-(3+5(x+3))=0
We multiply parentheses
9x-(3+5(x+3))-6=0
We calculate terms in parentheses: -(3+5(x+3)), so:We get rid of parentheses
3+5(x+3)
determiningTheFunctionDomain 5(x+3)+3
We multiply parentheses
5x+15+3
We add all the numbers together, and all the variables
5x+18
Back to the equation:
-(5x+18)
9x-5x-18-6=0
We add all the numbers together, and all the variables
4x-24=0
We move all terms containing x to the left, all other terms to the right
4x=24
x=24/4
x=6
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