3(3x-2)=64+40

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Solution for 3(3x-2)=64+40 equation: 



3(3x-2)=64+40

We move all terms to the left:

3(3x-2)-(64+40)=0

We add all the numbers together, and all the variables

3(3x-2)-104=0

We multiply parentheses

9x-6-104=0

We add all the numbers together, and all the variables

9x-110=0

We move all terms containing x to the left, all other terms to the right

9x=110

x=110/9

x=12+2/9

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