3(3x-2)=x+7+4x

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Solution for 3(3x-2)=x+7+4x equation: 



3(3x-2)=x+7+4x

We move all terms to the left:

3(3x-2)-(x+7+4x)=0

We add all the numbers together, and all the variables

3(3x-2)-(5x+7)=0

We multiply parentheses

9x-(5x+7)-6=0

We get rid of parentheses

9x-5x-7-6=0

We add all the numbers together, and all the variables

4x-13=0

We move all terms containing x to the left, all other terms to the right

4x=13

x=13/4

x=3+1/4

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