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3(3x-3)+15=2(x+5)
We move all terms to the left:
3(3x-3)+15-(2(x+5))=0
We multiply parentheses
9x-(2(x+5))-9+15=0
We calculate terms in parentheses: -(2(x+5)), so:We add all the numbers together, and all the variables
2(x+5)
We multiply parentheses
2x+10
Back to the equation:
-(2x+10)
9x-(2x+10)+6=0
We get rid of parentheses
9x-2x-10+6=0
We add all the numbers together, and all the variables
7x-4=0
We move all terms containing x to the left, all other terms to the right
7x=4
x=4/7
x=4/7
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