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3(3x-3)+5=4(x+4)
We move all terms to the left:
3(3x-3)+5-(4(x+4))=0
We multiply parentheses
9x-(4(x+4))-9+5=0
We calculate terms in parentheses: -(4(x+4)), so:We add all the numbers together, and all the variables
4(x+4)
We multiply parentheses
4x+16
Back to the equation:
-(4x+16)
9x-(4x+16)-4=0
We get rid of parentheses
9x-4x-16-4=0
We add all the numbers together, and all the variables
5x-20=0
We move all terms containing x to the left, all other terms to the right
5x=20
x=20/5
x=4
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