3(3x-3)-(x-5)=28

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Solution for 3(3x-3)-(x-5)=28 equation: 



3(3x-3)-(x-5)=28

We move all terms to the left:

3(3x-3)-(x-5)-(28)=0

We multiply parentheses

9x-(x-5)-9-28=0

We get rid of parentheses

9x-x+5-9-28=0

We add all the numbers together, and all the variables

8x-32=0

We move all terms containing x to the left, all other terms to the right

8x=32

x=32/8

x=4

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