3(3x-3)-4=3(x-2)+17

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Solution for 3(3x-3)-4=3(x-2)+17 equation: 



3(3x-3)-4=3(x-2)+17

We move all terms to the left:

3(3x-3)-4-(3(x-2)+17)=0

We multiply parentheses

9x-(3(x-2)+17)-9-4=0



We calculate terms in parentheses: -(3(x-2)+17), so:

3(x-2)+17

We multiply parentheses

3x-6+17

We add all the numbers together, and all the variables

3x+11

Back to the equation:

-(3x+11)



We add all the numbers together, and all the variables

9x-(3x+11)-13=0

We get rid of parentheses

9x-3x-11-13=0

We add all the numbers together, and all the variables

6x-24=0

We move all terms containing x to the left, all other terms to the right

6x=24

x=24/6

x=4

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