3(3x-3)=2(4x+4)+10

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Solution for 3(3x-3)=2(4x+4)+10 equation: 



3(3x-3)=2(4x+4)+10

We move all terms to the left:

3(3x-3)-(2(4x+4)+10)=0

We multiply parentheses

9x-(2(4x+4)+10)-9=0



We calculate terms in parentheses: -(2(4x+4)+10), so:

2(4x+4)+10

We multiply parentheses

8x+8+10

We add all the numbers together, and all the variables

8x+18

Back to the equation:

-(8x+18)



We get rid of parentheses

9x-8x-18-9=0

We add all the numbers together, and all the variables

x-27=0

We move all terms containing x to the left, all other terms to the right

x=27

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