3(3x-3)=2(4x+4)+10

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Solution for 3(3x-3)=2(4x+4)+10 equation:



3(3x-3)=2(4x+4)+10
We move all terms to the left:
3(3x-3)-(2(4x+4)+10)=0
We multiply parentheses
9x-(2(4x+4)+10)-9=0
We calculate terms in parentheses: -(2(4x+4)+10), so:
2(4x+4)+10
We multiply parentheses
8x+8+10
We add all the numbers together, and all the variables
8x+18
Back to the equation:
-(8x+18)
We get rid of parentheses
9x-8x-18-9=0
We add all the numbers together, and all the variables
x-27=0
We move all terms containing x to the left, all other terms to the right
x=27

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