3(3x-3)=2(x+3)

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Solution for 3(3x-3)=2(x+3) equation: 



3(3x-3)=2(x+3)

We move all terms to the left:

3(3x-3)-(2(x+3))=0

We multiply parentheses

9x-(2(x+3))-9=0



We calculate terms in parentheses: -(2(x+3)), so:

2(x+3)

We multiply parentheses

2x+6

Back to the equation:

-(2x+6)



We get rid of parentheses

9x-2x-6-9=0

We add all the numbers together, and all the variables

7x-15=0

We move all terms containing x to the left, all other terms to the right

7x=15

x=15/7

x=2+1/7

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