3(3x-3)=6x+12

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Solution for 3(3x-3)=6x+12 equation: 



3(3x-3)=6x+12

We move all terms to the left:

3(3x-3)-(6x+12)=0

We multiply parentheses

9x-(6x+12)-9=0

We get rid of parentheses

9x-6x-12-9=0

We add all the numbers together, and all the variables

3x-21=0

We move all terms containing x to the left, all other terms to the right

3x=21

x=21/3

x=7

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