3(3x-3)=7x+21

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Solution for 3(3x-3)=7x+21 equation: 



3(3x-3)=7x+21

We move all terms to the left:

3(3x-3)-(7x+21)=0

We multiply parentheses

9x-(7x+21)-9=0

We get rid of parentheses

9x-7x-21-9=0

We add all the numbers together, and all the variables

2x-30=0

We move all terms containing x to the left, all other terms to the right

2x=30

x=30/2

x=15

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