3(3x-4)-2(x-5)=x-4(x+5)-3(2x+1)

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Solution for 3(3x-4)-2(x-5)=x-4(x+5)-3(2x+1) equation: 



3(3x-4)-2(x-5)=x-4(x+5)-3(2x+1)

We move all terms to the left:

3(3x-4)-2(x-5)-(x-4(x+5)-3(2x+1))=0

We multiply parentheses

9x-2x-(x-4(x+5)-3(2x+1))-12+10=0



We calculate terms in parentheses: -(x-4(x+5)-3(2x+1)), so:

x-4(x+5)-3(2x+1)

We multiply parentheses

x-4x-6x-20-3

We add all the numbers together, and all the variables

-9x-23

Back to the equation:

-(-9x-23)



We add all the numbers together, and all the variables

7x-(-9x-23)-2=0

We get rid of parentheses

7x+9x+23-2=0

We add all the numbers together, and all the variables

16x+21=0

We move all terms containing x to the left, all other terms to the right

16x=-21

x=-21/16

x=-1+5/16

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