3(3x-4)-5=7x+20

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Solution for 3(3x-4)-5=7x+20 equation: 



3(3x-4)-5=7x+20

We move all terms to the left:

3(3x-4)-5-(7x+20)=0

We multiply parentheses

9x-(7x+20)-12-5=0

We get rid of parentheses

9x-7x-20-12-5=0

We add all the numbers together, and all the variables

2x-37=0

We move all terms containing x to the left, all other terms to the right

2x=37

x=37/2

x=18+1/2

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