3(3x-4)=14(32x+56)

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Solution for 3(3x-4)=14(32x+56) equation: 



3(3x-4)=14(32x+56)

We move all terms to the left:

3(3x-4)-(14(32x+56))=0

We multiply parentheses

9x-(14(32x+56))-12=0



We calculate terms in parentheses: -(14(32x+56)), so:

14(32x+56)

We multiply parentheses

448x+784

Back to the equation:

-(448x+784)



We get rid of parentheses

9x-448x-784-12=0

We add all the numbers together, and all the variables

-439x-796=0

We move all terms containing x to the left, all other terms to the right

-439x=796

x=796/-439

x=-1+357/439

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