3(3x-4)=6x-(x+8)

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Solution for 3(3x-4)=6x-(x+8) equation: 



3(3x-4)=6x-(x+8)

We move all terms to the left:

3(3x-4)-(6x-(x+8))=0

We multiply parentheses

9x-(6x-(x+8))-12=0



We calculate terms in parentheses: -(6x-(x+8)), so:

6x-(x+8)

We get rid of parentheses

6x-x-8

We add all the numbers together, and all the variables

5x-8

Back to the equation:

-(5x-8)



We get rid of parentheses

9x-5x+8-12=0

We add all the numbers together, and all the variables

4x-4=0

We move all terms containing x to the left, all other terms to the right

4x=4

x=4/4

x=1

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