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3(3x-5)+1=5(2+x)
We move all terms to the left:
3(3x-5)+1-(5(2+x))=0
We add all the numbers together, and all the variables
3(3x-5)-(5(x+2))+1=0
We multiply parentheses
9x-(5(x+2))-15+1=0
We calculate terms in parentheses: -(5(x+2)), so:We add all the numbers together, and all the variables
5(x+2)
We multiply parentheses
5x+10
Back to the equation:
-(5x+10)
9x-(5x+10)-14=0
We get rid of parentheses
9x-5x-10-14=0
We add all the numbers together, and all the variables
4x-24=0
We move all terms containing x to the left, all other terms to the right
4x=24
x=24/4
x=6
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