3(3x-5)+9=7x+4(x-3)+4

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Solution for 3(3x-5)+9=7x+4(x-3)+4 equation:



3(3x-5)+9=7x+4(x-3)+4
We move all terms to the left:
3(3x-5)+9-(7x+4(x-3)+4)=0
We multiply parentheses
9x-(7x+4(x-3)+4)-15+9=0
We calculate terms in parentheses: -(7x+4(x-3)+4), so:
7x+4(x-3)+4
We multiply parentheses
7x+4x-12+4
We add all the numbers together, and all the variables
11x-8
Back to the equation:
-(11x-8)
We add all the numbers together, and all the variables
9x-(11x-8)-6=0
We get rid of parentheses
9x-11x+8-6=0
We add all the numbers together, and all the variables
-2x+2=0
We move all terms containing x to the left, all other terms to the right
-2x=-2
x=-2/-2
x=1

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