3(3x-5)-4=3(x-5)+14

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Solution for 3(3x-5)-4=3(x-5)+14 equation: 



3(3x-5)-4=3(x-5)+14

We move all terms to the left:

3(3x-5)-4-(3(x-5)+14)=0

We multiply parentheses

9x-(3(x-5)+14)-15-4=0



We calculate terms in parentheses: -(3(x-5)+14), so:

3(x-5)+14

We multiply parentheses

3x-15+14

We add all the numbers together, and all the variables

3x-1

Back to the equation:

-(3x-1)



We add all the numbers together, and all the variables

9x-(3x-1)-19=0

We get rid of parentheses

9x-3x+1-19=0

We add all the numbers together, and all the variables

6x-18=0

We move all terms containing x to the left, all other terms to the right

6x=18

x=18/6

x=3

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