3(3x-5)-5=3(x-5)+43

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Solution for 3(3x-5)-5=3(x-5)+43 equation: 



3(3x-5)-5=3(x-5)+43

We move all terms to the left:

3(3x-5)-5-(3(x-5)+43)=0

We multiply parentheses

9x-(3(x-5)+43)-15-5=0



We calculate terms in parentheses: -(3(x-5)+43), so:

3(x-5)+43

We multiply parentheses

3x-15+43

We add all the numbers together, and all the variables

3x+28

Back to the equation:

-(3x+28)



We add all the numbers together, and all the variables

9x-(3x+28)-20=0

We get rid of parentheses

9x-3x-28-20=0

We add all the numbers together, and all the variables

6x-48=0

We move all terms containing x to the left, all other terms to the right

6x=48

x=48/6

x=8

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