3(3x-5)-7=4+2(8+6x)+3x

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Solution for 3(3x-5)-7=4+2(8+6x)+3x equation: 



3(3x-5)-7=4+2(8+6x)+3x

We move all terms to the left:

3(3x-5)-7-(4+2(8+6x)+3x)=0

We add all the numbers together, and all the variables

3(3x-5)-(4+2(6x+8)+3x)-7=0

We multiply parentheses

9x-(4+2(6x+8)+3x)-15-7=0



We calculate terms in parentheses: -(4+2(6x+8)+3x), so:

4+2(6x+8)+3x

determiningTheFunctionDomain
2(6x+8)+3x+4

We add all the numbers together, and all the variables

3x+2(6x+8)+4

We multiply parentheses

3x+12x+16+4

We add all the numbers together, and all the variables

15x+20

Back to the equation:

-(15x+20)



We add all the numbers together, and all the variables

9x-(15x+20)-22=0

We get rid of parentheses

9x-15x-20-22=0

We add all the numbers together, and all the variables

-6x-42=0

We move all terms containing x to the left, all other terms to the right

-6x=42

x=42/-6

x=-7

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