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3(3x-5)=30-3(x-3)
We move all terms to the left:
3(3x-5)-(30-3(x-3))=0
We multiply parentheses
9x-(30-3(x-3))-15=0
We calculate terms in parentheses: -(30-3(x-3)), so:We get rid of parentheses
30-3(x-3)
determiningTheFunctionDomain -3(x-3)+30
We multiply parentheses
-3x+9+30
We add all the numbers together, and all the variables
-3x+39
Back to the equation:
-(-3x+39)
9x+3x-39-15=0
We add all the numbers together, and all the variables
12x-54=0
We move all terms containing x to the left, all other terms to the right
12x=54
x=54/12
x=4+1/2
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