3(3x-6)-2=3(x-4)+16

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Solution for 3(3x-6)-2=3(x-4)+16 equation:



3(3x-6)-2=3(x-4)+16
We move all terms to the left:
3(3x-6)-2-(3(x-4)+16)=0
We multiply parentheses
9x-(3(x-4)+16)-18-2=0
We calculate terms in parentheses: -(3(x-4)+16), so:
3(x-4)+16
We multiply parentheses
3x-12+16
We add all the numbers together, and all the variables
3x+4
Back to the equation:
-(3x+4)
We add all the numbers together, and all the variables
9x-(3x+4)-20=0
We get rid of parentheses
9x-3x-4-20=0
We add all the numbers together, and all the variables
6x-24=0
We move all terms containing x to the left, all other terms to the right
6x=24
x=24/6
x=4

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