3(3x-6)-3=3(x-2)+21

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Solution for 3(3x-6)-3=3(x-2)+21 equation: 



3(3x-6)-3=3(x-2)+21

We move all terms to the left:

3(3x-6)-3-(3(x-2)+21)=0

We multiply parentheses

9x-(3(x-2)+21)-18-3=0



We calculate terms in parentheses: -(3(x-2)+21), so:

3(x-2)+21

We multiply parentheses

3x-6+21

We add all the numbers together, and all the variables

3x+15

Back to the equation:

-(3x+15)



We add all the numbers together, and all the variables

9x-(3x+15)-21=0

We get rid of parentheses

9x-3x-15-21=0

We add all the numbers together, and all the variables

6x-36=0

We move all terms containing x to the left, all other terms to the right

6x=36

x=36/6

x=6

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