3(3x-6)-5=3(x-2)+25

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Solution for 3(3x-6)-5=3(x-2)+25 equation: 



3(3x-6)-5=3(x-2)+25

We move all terms to the left:

3(3x-6)-5-(3(x-2)+25)=0

We multiply parentheses

9x-(3(x-2)+25)-18-5=0



We calculate terms in parentheses: -(3(x-2)+25), so:

3(x-2)+25

We multiply parentheses

3x-6+25

We add all the numbers together, and all the variables

3x+19

Back to the equation:

-(3x+19)



We add all the numbers together, and all the variables

9x-(3x+19)-23=0

We get rid of parentheses

9x-3x-19-23=0

We add all the numbers together, and all the variables

6x-42=0

We move all terms containing x to the left, all other terms to the right

6x=42

x=42/6

x=7

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