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3(3x-8)/2x-5=1/3
We move all terms to the left:
3(3x-8)/2x-5-(1/3)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
3(3x-8)/2x-5-(+1/3)=0
We get rid of parentheses
3(3x-8)/2x-5-1/3=0
We calculate fractions
(27x-72)/6x+(-2x)/6x-5=0
We multiply all the terms by the denominator
(27x-72)+(-2x)-5*6x=0
Wy multiply elements
(27x-72)+(-2x)-30x=0
We get rid of parentheses
27x-2x-30x-72=0
We add all the numbers together, and all the variables
-5x-72=0
We move all terms containing x to the left, all other terms to the right
-5x=72
x=72/-5
x=-14+2/5
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