3(3x-9)-3=3(x-4)+18

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Solution for 3(3x-9)-3=3(x-4)+18 equation: 



3(3x-9)-3=3(x-4)+18

We move all terms to the left:

3(3x-9)-3-(3(x-4)+18)=0

We multiply parentheses

9x-(3(x-4)+18)-27-3=0



We calculate terms in parentheses: -(3(x-4)+18), so:

3(x-4)+18

We multiply parentheses

3x-12+18

We add all the numbers together, and all the variables

3x+6

Back to the equation:

-(3x+6)



We add all the numbers together, and all the variables

9x-(3x+6)-30=0

We get rid of parentheses

9x-3x-6-30=0

We add all the numbers together, and all the variables

6x-36=0

We move all terms containing x to the left, all other terms to the right

6x=36

x=36/6

x=6

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