3(3x2,+12)=-2(3x2,-6)

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Solution for 3(3x2,+12)=-2(3x2,-6) equation: 



3(3x^2.+12)=-2(3x^2.-6)

We move all terms to the left:

3(3x^2.+12)-(-2(3x^2.-6))=0

We multiply parentheses

9x^2-(-2(3x^2.-6))+36=0



We calculate terms in parentheses: -(-2(3x^2.-6)), so:

-2(3x^2.-6)

We multiply parentheses

-6x^2+12

Back to the equation:

-(-6x^2+12)



We get rid of parentheses

9x^2+6x^2-12+36=0

We add all the numbers together, and all the variables

15x^2+24=0

a = 15; b = 0; c = +24;
Δ = b2-4ac
Δ = 02-4·15·24
Δ = -1440
Delta is less than zero, so there is no solution for the equation

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