3(3y+-6)=-18

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Solution for 3(3y+-6)=-18 equation: 



3(3y+-6)=-18

We move all terms to the left:

3(3y+-6)-(-18)=0

We add all the numbers together, and all the variables

3(3y-6)-(-18)=0

We add all the numbers together, and all the variables

3(3y-6)+18=0

We multiply parentheses

9y-18+18=0

We add all the numbers together, and all the variables

9y=0

y=0/9

y=0

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