3(3y+1)+4y=-28

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Solution for 3(3y+1)+4y=-28 equation: 



3(3y+1)+4y=-28

We move all terms to the left:

3(3y+1)+4y-(-28)=0

We add all the numbers together, and all the variables

4y+3(3y+1)+28=0

We multiply parentheses

4y+9y+3+28=0

We add all the numbers together, and all the variables

13y+31=0

We move all terms containing y to the left, all other terms to the right

13y=-31

y=-31/13

y=-2+5/13

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