3(3y+1)+4y=23

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Solution for 3(3y+1)+4y=23 equation: 



3(3y+1)+4y=23

We move all terms to the left:

3(3y+1)+4y-(23)=0

We add all the numbers together, and all the variables

4y+3(3y+1)-23=0

We multiply parentheses

4y+9y+3-23=0

We add all the numbers together, and all the variables

13y-20=0

We move all terms containing y to the left, all other terms to the right

13y=20

y=20/13

y=1+7/13

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