3(3y+1)+4y=23

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Solution for 3(3y+1)+4y=23 equation:



3(3y+1)+4y=23
We move all terms to the left:
3(3y+1)+4y-(23)=0
We add all the numbers together, and all the variables
4y+3(3y+1)-23=0
We multiply parentheses
4y+9y+3-23=0
We add all the numbers together, and all the variables
13y-20=0
We move all terms containing y to the left, all other terms to the right
13y=20
y=20/13
y=1+7/13

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