3(3y+1)-4(y-4)=29

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Solution for 3(3y+1)-4(y-4)=29 equation: 



3(3y+1)-4(y-4)=29

We move all terms to the left:

3(3y+1)-4(y-4)-(29)=0

We multiply parentheses

9y-4y+3+16-29=0

We add all the numbers together, and all the variables

5y-10=0

We move all terms containing y to the left, all other terms to the right

5y=10

y=10/5

y=2

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