3(3y+1)=9(y-2)+21

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Solution for 3(3y+1)=9(y-2)+21 equation: 



3(3y+1)=9(y-2)+21

We move all terms to the left:

3(3y+1)-(9(y-2)+21)=0

We multiply parentheses

9y-(9(y-2)+21)+3=0



We calculate terms in parentheses: -(9(y-2)+21), so:

9(y-2)+21

We multiply parentheses

9y-18+21

We add all the numbers together, and all the variables

9y+3

Back to the equation:

-(9y+3)



We get rid of parentheses

9y-9y-3+3=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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