3(3y+2)-2y=13

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Solution for 3(3y+2)-2y=13 equation: 



3(3y+2)-2y=13

We move all terms to the left:

3(3y+2)-2y-(13)=0

We add all the numbers together, and all the variables

-2y+3(3y+2)-13=0

We multiply parentheses

-2y+9y+6-13=0

We add all the numbers together, and all the variables

7y-7=0

We move all terms containing y to the left, all other terms to the right

7y=7

y=7/7

y=1

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