3(3y+2)-6=18

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Solution for 3(3y+2)-6=18 equation: 



3(3y+2)-6=18

We move all terms to the left:

3(3y+2)-6-(18)=0

We add all the numbers together, and all the variables

3(3y+2)-24=0

We multiply parentheses

9y+6-24=0

We add all the numbers together, and all the variables

9y-18=0

We move all terms containing y to the left, all other terms to the right

9y=18

y=18/9

y=2

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