3(3y+2)=40

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Solution for 3(3y+2)=40 equation: 



3(3y+2)=40

We move all terms to the left:

3(3y+2)-(40)=0

We multiply parentheses

9y+6-40=0

We add all the numbers together, and all the variables

9y-34=0

We move all terms containing y to the left, all other terms to the right

9y=34

y=34/9

y=3+7/9

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