3(3y+3)-2=7y+7

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Solution for 3(3y+3)-2=7y+7 equation: 



3(3y+3)-2=7y+7

We move all terms to the left:

3(3y+3)-2-(7y+7)=0

We multiply parentheses

9y-(7y+7)+9-2=0

We get rid of parentheses

9y-7y-7+9-2=0

We add all the numbers together, and all the variables

2y=0

y=0/2

y=0

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