3(3y+3)-3=2y+41

Solution for 3(3y+3)-3=2y+41 equation:

Simplifying
3(3y + 3) + -3 = 2y + 41

Reorder the terms:
3(3 + 3y) + -3 = 2y + 41
(3 * 3 + 3y * 3) + -3 = 2y + 41
(9 + 9y) + -3 = 2y + 41

Reorder the terms:
9 + -3 + 9y = 2y + 41

Combine like terms: 9 + -3 = 6
6 + 9y = 2y + 41

Reorder the terms:
6 + 9y = 41 + 2y

Solving
6 + 9y = 41 + 2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2y' to each side of the equation.
6 + 9y + -2y = 41 + 2y + -2y

Combine like terms: 9y + -2y = 7y
6 + 7y = 41 + 2y + -2y

Combine like terms: 2y + -2y = 0
6 + 7y = 41 + 0
6 + 7y = 41

Add '-6' to each side of the equation.
6 + -6 + 7y = 41 + -6

Combine like terms: 6 + -6 = 0
0 + 7y = 41 + -6
7y = 41 + -6

Combine like terms: 41 + -6 = 35
7y = 35

Divide each side by '7'.
y = 5

Simplifying
y = 5