3(3y+4)=4(2y-1)

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Solution for 3(3y+4)=4(2y-1) equation: 



3(3y+4)=4(2y-1)

We move all terms to the left:

3(3y+4)-(4(2y-1))=0

We multiply parentheses

9y-(4(2y-1))+12=0



We calculate terms in parentheses: -(4(2y-1)), so:

4(2y-1)

We multiply parentheses

8y-4

Back to the equation:

-(8y-4)



We get rid of parentheses

9y-8y+4+12=0

We add all the numbers together, and all the variables

y+16=0

We move all terms containing y to the left, all other terms to the right

y=-16

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