3(3y+4y-7)=42

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Solution for 3(3y+4y-7)=42 equation: 



3(3y+4y-7)=42

We move all terms to the left:

3(3y+4y-7)-(42)=0

We add all the numbers together, and all the variables

3(7y-7)-42=0

We multiply parentheses

21y-21-42=0

We add all the numbers together, and all the variables

21y-63=0

We move all terms containing y to the left, all other terms to the right

21y=63

y=63/21

y=3

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