3(3y+5)+5=10(y+2)-y

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Solution for 3(3y+5)+5=10(y+2)-y equation:


Simplifying
3(3y + 5) + 5 = 10(y + 2) + -1y

Reorder the terms:
3(5 + 3y) + 5 = 10(y + 2) + -1y
(5 * 3 + 3y * 3) + 5 = 10(y + 2) + -1y
(15 + 9y) + 5 = 10(y + 2) + -1y

Reorder the terms:
15 + 5 + 9y = 10(y + 2) + -1y

Combine like terms: 15 + 5 = 20
20 + 9y = 10(y + 2) + -1y

Reorder the terms:
20 + 9y = 10(2 + y) + -1y
20 + 9y = (2 * 10 + y * 10) + -1y
20 + 9y = (20 + 10y) + -1y

Combine like terms: 10y + -1y = 9y
20 + 9y = 20 + 9y

Add '-20' to each side of the equation.
20 + -20 + 9y = 20 + -20 + 9y

Combine like terms: 20 + -20 = 0
0 + 9y = 20 + -20 + 9y
9y = 20 + -20 + 9y

Combine like terms: 20 + -20 = 0
9y = 0 + 9y
9y = 9y

Add '-9y' to each side of the equation.
9y + -9y = 9y + -9y

Combine like terms: 9y + -9y = 0
0 = 9y + -9y

Combine like terms: 9y + -9y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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