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3(3y+5)=2(5y+5)
We move all terms to the left:
3(3y+5)-(2(5y+5))=0
We multiply parentheses
9y-(2(5y+5))+15=0
We calculate terms in parentheses: -(2(5y+5)), so:We get rid of parentheses
2(5y+5)
We multiply parentheses
10y+10
Back to the equation:
-(10y+10)
9y-10y-10+15=0
We add all the numbers together, and all the variables
-1y+5=0
We move all terms containing y to the left, all other terms to the right
-y=-5
y=-5/-1
y=+5
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