3(3y+6)=7y+18+2y

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Solution for 3(3y+6)=7y+18+2y equation: 



3(3y+6)=7y+18+2y

We move all terms to the left:

3(3y+6)-(7y+18+2y)=0

We add all the numbers together, and all the variables

3(3y+6)-(9y+18)=0

We multiply parentheses

9y-(9y+18)+18=0

We get rid of parentheses

9y-9y-18+18=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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