3(3y-2)+3y-2=7(2y+2)

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Solution for 3(3y-2)+3y-2=7(2y+2) equation: 



3(3y-2)+3y-2=7(2y+2)

We move all terms to the left:

3(3y-2)+3y-2-(7(2y+2))=0

We add all the numbers together, and all the variables

3y+3(3y-2)-(7(2y+2))-2=0

We multiply parentheses

3y+9y-(7(2y+2))-6-2=0



We calculate terms in parentheses: -(7(2y+2)), so:

7(2y+2)

We multiply parentheses

14y+14

Back to the equation:

-(14y+14)



We add all the numbers together, and all the variables

12y-(14y+14)-8=0

We get rid of parentheses

12y-14y-14-8=0

We add all the numbers together, and all the variables

-2y-22=0

We move all terms containing y to the left, all other terms to the right

-2y=22

y=22/-2

y=-11

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