3(3y-2)+4y=20

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Solution for 3(3y-2)+4y=20 equation: 



3(3y-2)+4y=20

We move all terms to the left:

3(3y-2)+4y-(20)=0

We add all the numbers together, and all the variables

4y+3(3y-2)-20=0

We multiply parentheses

4y+9y-6-20=0

We add all the numbers together, and all the variables

13y-26=0

We move all terms containing y to the left, all other terms to the right

13y=26

y=26/13

y=2

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